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nik		#1 Posted : 01 February 2015 05:11:42(UTC)
Rank: Newbie Groups: Registered Joined: 01/02/2015(UTC) Posts: 4		Hi all, some problem which unit calculation K:8.87 α:1 β:0.43 γ:0 b:200*'мм Kα:K*(α+(β*{α^2}/{b^2})+(γ*{α^4}/{b^4}))^0.5=# result: Unit does not match((((
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Davide Carpi		#2 Posted : 01 February 2015 15:39:04(UTC)
Rank: Advanced Member Groups: Registered, Advanced Member Joined: 13/01/2012(UTC) Posts: 2,647 Location: Italy Was thanked: 1329 time(s) in 875 post(s)		The error seems correct. Just make a dimensional analysis on α+(β*{α^2}/{b^2})+(γ*{α^4}/{b^4}) You sum something dimensionless with 1/мм^2 and 1/мм^4 Edited by user 01 February 2015 15:41:03(UTC)  | Reason: Not specified
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nik		#3 Posted : 03 February 2015 01:45:39(UTC)
Rank: Newbie Groups: Registered Joined: 01/02/2015(UTC) Posts: 4		Originally Posted by: w3b5urf3r_reloaded The error seems correct. Just make a dimensional analysis on α+(β*{α^2}/{b^2})+(γ*{α^4}/{b^4}) You sum something dimensionless with 1/мм^2 and 1/мм^4 I`m not convert unit of measure, math operation only value. mm^4 you real?? what a dimension, square? cube or astral?
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Davide Carpi		#4 Posted : 03 February 2015 02:11:26(UTC)
Rank: Advanced Member Groups: Registered, Advanced Member Joined: 13/01/2012(UTC) Posts: 2,647 Location: Italy Was thanked: 1329 time(s) in 875 post(s)		Maybe the attached picture helps a little bit more to understand the issue... As stated previously, you can't sum apples and oranges; therefore the error message seems consistent... Edited by user 03 February 2015 11:12:31(UTC)  | Reason: Not specified Davide Carpi attached the following image(s):
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nik		#5 Posted : 04 February 2015 00:46:44(UTC)
Rank: Newbie Groups: Registered Joined: 01/02/2015(UTC) Posts: 4		ок, ??? formula Edited by user 04 February 2015 00:53:47(UTC)  | Reason: Not specified
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Davide Carpi		#6 Posted : 04 February 2015 01:20:22(UTC)
Rank: Advanced Member Groups: Registered, Advanced Member Joined: 13/01/2012(UTC) Posts: 2,647 Location: Italy Was thanked: 1329 time(s) in 875 post(s)		Thanks for sharing the original formula, this makes more sense; seems you have missed or merged a parameter (alpha) with a variable (a) Best regards, Davide Edited by user 04 February 2015 01:40:15(UTC)  | Reason: Not specified File Attachment(s): nik.sm (18kb) downloaded 16 time(s). Davide Carpi attached the following image(s):
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nik		#7 Posted : 05 February 2015 00:04:59(UTC)
Rank: Newbie Groups: Registered Joined: 01/02/2015(UTC) Posts: 4		this is font trouble, real value "a"
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Davide Carpi		#8 Posted : 05 February 2015 01:20:46(UTC)
Rank: Advanced Member Groups: Registered, Advanced Member Joined: 13/01/2012(UTC) Posts: 2,647 Location: Italy Was thanked: 1329 time(s) in 875 post(s)		Seems strange, because in this way the formula has both mathematical sense (alpha*x^0+beta*x^2+gamma*x^4) and physical sense (homogenous units involved in the calculation)... there is some literature about this formula? (where it is used? has an author?) Edited by user 05 February 2015 01:30:12(UTC)  | Reason: Not specified
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