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Offline Everontt  
#1 Posted : 08 March 2018 16:51:34(UTC)
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Hello,

I wonder why left matrix give error and right is ok?

Best.

Test1.sm (55kb) downloaded 28 time(s).

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Offline Jean Giraud  
#2 Posted : 08 March 2018 20:21:56(UTC)
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Originally Posted by: Everontt Go to Quoted Post
I wonder why left matrix give error and right is ok?


They are identical, but the left one is incompletely dressed.
I don't understand the project. There is nothing more confusing
than subscripts. They are useful if the subscript is a long explicative definition.

Test1(1).sm (60kb) downloaded 17 time(s).
Offline CBG  
#3 Posted : 08 March 2018 23:46:08(UTC)
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I think some definitions are missing


Test(1).png



Best regards


Carlos
Offline mkraska  
#4 Posted : 09 March 2018 00:34:46(UTC)
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Originally Posted by: CBG Go to Quoted Post
I think some definitions are missing




No, it's the operator formatting of the built-in minor() function. Can be found on the Matrix palette.
Martin Kraska

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Offline CBG  
#5 Posted : 09 March 2018 00:47:59(UTC)
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Ufss!!! Sorry !!!

You are right.

How I did not see it defined in the floating panel?

Thank you

Carlos
Offline Jean Giraud  
#6 Posted : 09 March 2018 05:37:53(UTC)
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Originally Posted by: CBG Go to Quoted Post
I think some definitions are missing

I think it is => this from the palette

MatrixSomething.PNG

Offline Jean Giraud  
#7 Posted : 09 March 2018 07:39:56(UTC)
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Originally Posted by: Jean Giraud Go to Quoted Post
I think it is =


Some kind of matrix logic ... logic & ½
Not familiar at all, no recollection from Mathcad.
Is it really productive fro the collab originator ?

Jean

Utilities Matrix UNKNOWN Palette.sm (20kb) downloaded 16 time(s).
Offline Davide Carpi  
#8 Posted : 09 March 2018 11:30:43(UTC)
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Seems some issue in the symbolic engine about the inversion of minor() when there are units

Originally Posted by: Everontt Go to Quoted Post
I wonder why left matrix give error and right is ok?


Because the right one comes from an if/else, that force a numerical optimization context while in the left case it's in a symbolic context.

To figure out the difference between K.1 and K.2, look at their content
  • add a breakpoint on Mxx and look what it happens inside the loop in the 2 cases
  • alternatively write on the canvas K.1= and K.2= with "none" optimization


2018-03-09 09_33_13-SMath Studio - [Test1.sm_].png

Edited by user 09 March 2018 12:08:11(UTC)  | Reason: typo

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Offline Jean Giraud  
#9 Posted : 09 March 2018 18:27:50(UTC)
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Originally Posted by: Davide Carpi Go to Quoted Post
Because the right one comes from an if/else, that force a numerical optimization context while in the left case it's in a symbolic contex


About all that: my understanding is only slightly pregnant !
It resumes to solving a tridiagonal system c/w units
conclusively resulting in valued units and coefficients.
Most interesting for more bed time reading.

Thanks to all ... Jean

Maths Tridiagonal [Unknown Units].sm (142kb) downloaded 16 time(s).

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