  Rank: Advanced Member Groups: Registered, Advanced Member Joined: 13/01/2012(UTC) Posts: 2,725   Location: Italy Was thanked: 1393 time(s) in 909 post(s)
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Hi, I found this bug defining user functions with IsString() The issue disappear using IsString inside line() regards, w3b5urf3r Edited by moderator 19 January 2016 16:44:41(UTC)
| Reason: edit for attach migration tests File Attachment(s): Davide Carpi attached the following image(s): |
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 Rank: Newbie
Groups: Registered
Joined: 16/06/2012(UTC) Posts: 7  Location: Home Counties
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Originally Posted by: w3b5urf3r_reloaded  Hi,
I found this bug defining user functions with IsString()
The issue disappear using IsString inside line()
regards,
w3b5urf3r I'm not sure whether this is a bug or a delayed-evaluation 'feature' of using/not-using the program line. I raised a similar question about a month ago ... Originally Posted by: Stuart Bruff Hello,
How is the equality (ctl-=) operator supposed to work? I get ([1]=1)=1 but ([1])=2; the latter I expect, but I am surprised that a matrix is equal to a scalar, even though it is just a single element matrix.
Is there a way of programmatically distinguishing between a scalar and an array? I know there's no IsScalar or IsArray function. I've seen the workaround for using num2str & mat and I've written a function
IsArray(x):=
|n:=findstr(num2str(x),"mat" )
|n<>-1
(why doesn't IsArray(x):=findstr(num2str(x),"mat" )<>-1 work?)
, but this would appear to impose quite an evaluation overhead for large matrices. I was hoping to use x=stack(x) to check if x was an array, hence the purpose of my original question.
Stuart
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  Rank: Administration Groups: Developers, Registered, Knovel Developers, Administrators, Advanced Member Joined: 11/07/2008(UTC) Posts: 1,636  Was thanked: 2007 time(s) in 677 post(s)
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Thank you! Fixed. Regards. Andrey Ivashov attached the following image(s):
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 2 users thanked Andrey Ivashov for this useful post.
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on 30/07/2012(UTC), on 30/07/2012(UTC)
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