Rank: Member Groups: Registered
Joined: 19/11/2013(UTC) Posts: 17
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I want to have mm units. But I still have the situation like on the screen shot. Dont understand why and dont know what can I do to resolve the problem. When the argument of the square root is the number the value and units are ok. When there is the variable - everything is bad. Jadalbert attached the following image(s):
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Rank: Advanced Member Groups: Registered
Joined: 15/04/2012(UTC) Posts: 1,986 Was thanked: 1124 time(s) in 721 post(s)
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You cannot expect the square root of a length (given in mm) to be of dimension length. That would mean you would expect length times length to be of dimension length instead of area. Thus your equation might be designed for dimension- or unit-free values, how they are sometimes still in use. They require you to put in the data in certain units and deliver the result also in certain units. If you use such equations with variables containing value and unit, you first must divide the input by the required input unit and take the result times the expected results units. I'd try to avoid this, because this procedure is far from self documenting. Try to use equations involving just real physical quantities regardless of their units. SMath is ideally suited to handle such equations. |
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Rank: Member Groups: Registered
Joined: 19/11/2013(UTC) Posts: 17
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It has sense! Thank You for advice.
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