 Rank: Newbie
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Joined: 25/02/2020(UTC)
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Hi everyone, I've got problem with 'if' statement. Image: https://ibb.co/YcxjcqRAs you can see in the picture, y(3) is being counted by the second formula, but it must be counted by the third formula cos' x>2 and it must be equal 1. What's wrong with that? Thanks! You can also download the original file by this link: https://ufile.io/qpnqpws9 (I could upload it on this forum, but it's stuck) Note (English is not my native language, so I'm sorry if something incorrect) Edited by user 25 February 2020 23:34:03(UTC)
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  Rank: Advanced Member Groups: Registered
Joined: 23/03/2016(UTC) Posts: 276  Was thanked: 91 time(s) in 57 post(s)
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The formulation you have for the second if statement will always evaluate to true if reached. If you look at your condition: (0<=x)< 2 (0<=x) will evaluate to 1 if true or 0 if false. Both 1 and 0 are less than 2. So will always evaluate to true because 1 < 2 is true and 0 < 2 is also true. Attached is the proper way to perform that condition in SMATH  2.sm (8kb) downloaded 18 time(s).Also the way that you have formulated the if statement f(2) will result in an error because none is not defined. If that's what you intend, that's fine. Otherwise you'd need equality <= or >= in the 2,3 if statement, respectively. Edited by user 25 February 2020 23:23:33(UTC)
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Joined: 04/07/2015(UTC) Posts: 6,866  Was thanked: 981 time(s) in 809 post(s)
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Originally Posted by: NØ  You can also download the original file No point => that gadget is freak. 
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