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Pick a number from a list if condition is meet
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Joined: 12/03/2024(UTC) Posts: 10  Was thanked: 1 time(s) in 1 post(s)
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How can i pick a speed based on a "n" value.  Let's say my n= 13 i want to get the value 30km/h for V, but if its 8 i want 60km/h. I have tried with for/while/if. But im guessing im doing something wrong or i don't know what to write exactly.  Any help is much apprecite it!
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Originally Posted by: mkraska  Thank you for the answer, but this doesn't help me. Or i don't understand it  . Example, i have N=10, based on N i want to get V. V for N=10 it's from here:  , but if i change N to 9 i want to obtain V=30km/hr. Thing is i have 8 variable based on N, and i want to obtain the values only by changing N. Sorry if i don't explain very well.
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The procedure is to get a vector of the potential values which can then be accessed by index. You also could implement it as a function v(n) = 30 + mod(n-1, 4)*10  |
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Originally Posted by: mkraska The procedure is to get a vector of the potential values which can then be accessed by index. You also could implement it as a function v(n) = 30 + mod(n-1, 4)*10 Great it works now. I just have to figure it out how to implement it for the rest of the file  . Thank you very much! How would you tackle this one?  Edited by user 13 March 2024 01:42:46(UTC)
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Originally Posted by: Obliterate Great it works now. I just have to figure it out how to implement it for the rest of the file . Thank you very much! How would you tackle this one? Divide n by 2, a bit of rounding and offset adjustment should do the job. |
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Originally Posted by: mkraska Originally Posted by: Obliterate Great it works now. I just have to figure it out how to implement it for the rest of the file . Thank you very much! How would you tackle this one? Divide n by 2, a bit of rounding and offset adjustment should do the job. I can't seem to get it to work, and for next examples i need to match it with a list that has some randomnes in number list. Isn't there a way i can create a list of number and if my "n" matches that list then i can get the correct value? I tried with for, if and so on. but im still a newbie in Smath. Thank you once again!
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If you have a limited set of choiches, this might be a solution.  Also, I think Martin has a point, since these "n" values should come from some formula. Edited by user 19 March 2024 04:39:52(UTC)
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Rank: Advanced Member Groups: Registered
Joined: 15/04/2012(UTC) Posts: 1,987 Was thanked: 1124 time(s) in 721 post(s)
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Originally Posted by: Obliterate Originally Posted by: mkraska Originally Posted by: Obliterate Great it works now. I just have to figure it out how to implement it for the rest of the file . Thank you very much! How would you tackle this one? Divide n by 2, a bit of rounding and offset adjustment should do the job. I can't seem to get it to work, and for next examples i need to match it with a list that has some randomnes in number list. Isn't there a way i can create a list of number and if my "n" matches that list then i can get the correct value? I tried with for, if and so on. but im still a newbie in Smath. Thank you once again! If there is no rule, then you have to provide a vector with values and adress it with index n. A simple lookup table by index. Fill the vector by hand, by reading a file or asking a chatbot. |
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Originally Posted by: Davide Carpi If you have a limited set of choiches, this might be a solution. Also, I think Martin has a point, since these "n" values should come from some formula. This works but i have other areas with diferent increment and i can't control them with interval. I will list a few of them:  here is 1,2,3 then goes to 16,17,18 then 26,27,28. So i have this interval from the picture above and the one before with "Latimea benzii".
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Rank: Member Groups: Registered
Joined: 12/03/2024(UTC) Posts: 10 Was thanked: 1 time(s) in 1 post(s)
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Originally Posted by: Obliterate Originally Posted by: Davide Carpi If you have a limited set of choiches, this might be a solution. Also, I think Martin has a point, since these "n" values should come from some formula. This works but i have other areas with diferent increment and i can't control them with interval. I will list a few of them: here is 1,2,3 then goes to 16,17,18 then 26,27,28. So i have this interval from the picture above and the one before with "Latimea benzii". Found a not very fancy solution, but it works .  pick a number from a list.sm (7kb) downloaded 3 time(s).
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